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Re: [10GBT] Framing question


It's clear in the diagram that 825 bits are designated to be encoded by the LDPC encoder.
So, 825 bits + 8 pad bits are encoded by LDPC (1024,833) to generate 191 parity check bits.
The total coded bits are 825 + 191 = 1016.
There are 127 4DPAM12 symbols and each carries 8 coded bits, 127 * 8 = 1016.


-----Original Message-----
From: stds-802-3-10gbt@IEEE.ORG [mailto:stds-802-3-10gbt@IEEE.ORG]On
Behalf Of sailesh rao
Sent: Wednesday, October 06, 2004 4:24 AM
Subject: [10GBT] Framing question

Hi All,

The available coded bits in the framing shown on slide 17 of
tellado_1_0904.pdf can be computed as

Number of PAM symbols: 1 4DPAM2 + 1 4DPAM12 + 126 4DPAM12T
Number of coded bits:       4bits      +    8 bits       + 126*8 bits
          = 1020 bits

Therefore, how are the remaining 4 bits in the 1024 LDPC block being


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