# Re: [10GBT] Framing question

Sailesh,
It's clear in the diagram that 825 bits are designated to be encoded by the LDPC encoder.
So, 825 bits + 8 pad bits are encoded by LDPC (1024,833) to generate 191 parity check bits.
The total coded bits are 825 + 191 = 1016.
There are 127 4DPAM12 symbols and each carries 8 coded bits, 127 * 8 = 1016.
Brett
-----Original Message-----
From: stds-802-3-10gbt@IEEE.ORG [mailto:stds-802-3-10gbt@IEEE.ORG]On
Behalf Of sailesh rao
Sent: Wednesday, October 06, 2004 4:24 AM
To: STDS-802-3-10GBT@listserv.ieee.org
Subject: [10GBT] Framing question
Hi All,
The available coded bits in the framing shown on slide 17 of
tellado_1_0904.pdf can be computed as
Number of PAM symbols: 1 4DPAM2 + 1 4DPAM12 + 126 4DPAM12T
Number of coded bits: 4bits + 8 bits + 126*8 bits
= 1020 bits
Therefore, how are the remaining 4 bits in the 1024 LDPC block being
modulated?
Thanks,
Sailesh.
srao@phyten.com
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