Re: Does Ten-Gigabit Ethernet need fault tolerance?
When implemented how fast is the FT traffic restoration of P802.3ad supposed to
work? From that restoration time, calculate how much data got lost. One of the
major features of tightly coupled error detection is that the traffic
restoration times are greatly reduced. At present, the fastest that L3 Matrix
(I can not use any vendor implementation names.), MPLS, or L1/REI/L3 is proposed
is 10 times slower than 802.3 that is directly mapped into SONET. (There are
several transport vendors that are doing this.) There are other issues with
fiber maintenance that have not been issues before because the amount of
aggregated data and the "round the clock" that 10GbE will likely see. This
makes the FT as much a function of the PHY as anywhere else.
"Mick Sea,man" wrote:
> What needs to be built in is the detection of failure. What we don't need to
> do is to build everything into the MAC. I suggest you look at the fault
> tolerant capabilities provided by P802.3ad and the work on Rapid
> Reconfiguration starting in 802.1.
> Both these (will) provide a degree of fault tolerance based on using
> protocols that are independent of MAC details to allow network nodes to
> precalculate their response to a low level indication of failure. There is
> really no need to build these protocols into the MAC.
> -----Original Message-----
> From: owner-stds-802-3-hssg@xxxxxxxxxxxxxxxxxx
> [mailto:owner-stds-802-3-hssg@xxxxxxxxxxxxxxxxxx]On Behalf Of Joe Gwinn
> Sent: Friday, July 16, 1999 3:15 PM
> To: stds-802-3-hssg@xxxxxxxx
> Subject: Does Ten-Gigabit Ethernet need fault tolerance?
> The purpose of this note is to present a case for inclusion of fault
> tolerance in 10GbE, and to offer a suitable proven technology for
> consideration. However, no salesman will call.
> Why Fault Tolerance? Ten-Gigabit Ethernet is going to be a relatively
> expensive, high-performance technology intended for major backbones,
> perhaps even nibbling at the bottom end of the wide-area network (WAN)
> market. In such applications, high availability is very much desired; loss
> of such a backbone or WAN is much too disruptive (and therefore expensive)
> to be much tolerated, and this kind of a market will gladly pay a
> reasonable premium to achieve the needed fault tolerance.
> Why add Fault Tolerance now? Because it's easiest (and thus cheapest) if
> done from the start, and because having FT built in and therefore becoming
> ubiquitous will be a competitive discriminator, neutralizing one of the
> remaining claimed advantages of ATM.
> Isn't Fault Tolerance difficult? In hub-and-spoke (logical star, physical
> loop) topologies such as GbE and10GbE, it's not hard to achieve both fault
> tolerance (FT) and military-level damage tolerance (DT). In networks of
> unrestricted topology, it's a lot harder. The presence of bridges does not
> affect this conclusion.
> How do I know that FT is so easily achieved? Because it's already been
> done, may be bought commercially, and is in use on one military system and
> is proposed for others. The FT/DT technology mentioned here was developed
> on a US Navy project, and is publically available without intellectual
> property restrictions. Why was the technology made public? To encourage
> its adopotion and use in COTS products, so that defense contractors can buy
> FT/DT lans from catalogs, rather than having to develop them again and
> again, at great risk and expense.
> What is the difference between Fault Tolerance and Damage Tolerance? In
> fault tolerance, faults are rare and do not correlate in either time or
> place. The classic example is the random failure of hardware components.
> (Small acts of damage, such as somebody tripping over a wire or breaking a
> connector somewhere, are treated as faults here because they are also rare
> and uncorrelated.) In damage tolerance, the individual faults are sharply
> correlated in time and place, and are often massive in number. The classic
> military example is a weapon strike. In the commercial world, a major power
> failure is a good example. Damage tolerance is considered much harder to
> accomplish than fault tolerance. If you have damage tolerance, you also
> have fault tolerance, but fault tolerance does not by itself confer damage
> How is this Damage Tolerance achieved? All changes in LAN segment topology
> (the loss or gain of nodes (NICs), hubs, or fibers) are detected in MAC
> hardware by the many link receivers, which report both loss and acquisition
> of modulated light. This surveillance occurs all the time on all links, and
> is independent of data traffic. Any change in topology provokes the
> hardware into "rostering mode", the automatic exploration of the segment
> using a flood of special "roster" packets to find the best path, where
> "best" is defined as that path which includes the maximum number of nodes
> Just how fault tolerant and damage tolerant is this scheme? A segment will
> work properly with any number of nodes and hubs, if sufficient fibers
> survive to connect them together, and will automatically configure itself
> into a working segment within a millisecond of the last fault. If the
> number of broken fibers is less than the number of hubs, all surviving
> nodes will remain accessible, regardless of the fault pattern. If the
> number of fiber breaks is equal to or greater than the number of hubs,
> there is a simple equation to predict the probability of loss of access to
> a typical node due to loss of hubs and/or fibers, given only the number of
> hubs and the probability of any fiber breaking: Pnd[p,r]= ((2p)(1-p))^r,
> where p is the probability of fiber breakage and r is the number of
> surviving hubs (which ranges from zero to four in a quad system). This
> equation is exact (to within 1%) for fiber breakage probabilities of 33% or
> less, and applies for any number of hubs.
> The simplicity of this equation is a consequence of the simplicity of this
> protocol, which is currently implemented in standard-issue FPGAs (not
> ASICs), and works without software intervention. It can also be
> implemented in firmware.
> To give a numerical example, in a 33-node 4-hub segment, loss of 42 fibers
> (16% of the segment's 264 fibers) would lead to only 0.5% of the nodes
> becoming inaccessible, on average. Said another way, after 42 fiber breaks,
> there are only five chances out of a thousand that a node will become
> inaccessible. This is very heavy damage, with one fiber in six broken. To
> take a more likely example, with three broken fibers, all nodes will be
> accessible, and with four broken fibers, there is less than one chance in a
> million that a node will become inaccessible. Recovery takes two ring tour
> times plus settling time (electrical plus mechanical), typically less than
> one millisecond in ship-size networks, measured from the last fault.
> Chattering and/or intermittent faults can be handled by a number of
> mechanisms, including delaying node entry by up to one second. Few current
> LAN technologies approach this degree of resilience, or speed of recovery.
> In commercial systems and some military systems, a dual-ring solution is
> sufficient. Up to quad-ring solutions are comercially available, needed
> for some military systems. However, the ability to support up to quad
> redundant systems should be provided in 10GbE, for two reasons. First,
> quad is needed for the military market, which may be economically
> significant in the early years of 10GbE. Second, quad provides a clear
> growth path and a way to reassure non-military customers that their most
> stringent problems can be solved: One can ask them if their needs really
> exceed those of warships duelling with supersonic missiles.
> The basic technical document, the RTFC Principles of Operation, is on the
> GbE website as "http://grouper.ieee.org/ groups/802/3/ 10G_study/public/
> email_attach/ gwinn_1_0699.pdf" and "http://grouper.ieee.org/
> groups/802/3/10G_study/ public/ email_attach/ gwinn_2_0699.pdf". I was a
> member of the team that developed the technology, and am the author of
> these documents.
> Although these documents assume RTFC, a form of distributed shared memory,
> the basic rostering technology can easily be adapted for Gigabit and
> Ten-Gigabit Ethernet as well. For nontechnical reasons, RTFC originally
> favored smart nodes connected via dumb hubs. However, the overall design
> can be somewhat simplified if one goes the other way, to dumb nodes and
> smart hubs. This also allows the same dumb nodes to be used in both non-FT
> and FT networks, increasing node production volume, and does not force
> users to throw nodes away to upgrade to FT.
> I therefore would submit that 10GbE would greatly benefit from fault
> tolerance, and also that it's very easily achieved if included in the
> original design of 10GbE.
> Joe Gwinn