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*To*: stds-802-3-hssg@xxxxxxxx*Subject*: Question on the Maximum number of packets per second*From*: "Joshua J. Brickel" <joshua.b@xxxxxxxxxx>*Date*: Thu, 31 May 2001 10:06:06 +0200*Sender*: owner-stds-802-3-hssg@xxxxxxxxxxxxxxxxxx

I was wondering if to find for 10GbE the maximum number of packets that will enter on an interface per unit time can be calculated as follows... 64bytes for minimum packet + 8 Bytes Preamble/SFD + 12 Bytes IPG/EFD = 84 bytes = 672 bits Then the maximum number of these minimum sized packets would be 10E+10/672 = 14.881 MP/s This would seem correct, except that I have not included how much off the transmitters clock can be. Can this significantly alter the numbers I have above? If anyone has any insight as to how fast a clock could be off of the nominal 10 gigabit rate and still be considered compliant I would appreciate it posted. Thanks, Joshua

**Follow-Ups**:**[802.3ae] Re: Question on the Maximum number of packets per second***From:*Roy Bynum

**Re: Question on the Maximum number of packets per second***From:*Sanjeev Mahalawat

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