Question on the Maximum number of packets per second

["Joshua J. Brickel" <joshua.b@teraop.com>]

I was wondering if to find for 10GbE the maximum number of packets that will
enter on an interface per unit time can be calculated as follows...

64bytes for minimum packet + 8 Bytes Preamble/SFD + 12 Bytes IPG/EFD = 84
bytes = 672 bits 

Then the maximum number of these minimum sized packets would be 10E+10/672 =
14.881 MP/s

This would seem correct, except that I have not included how much off the
transmitters clock can be.  Can this significantly alter the numbers I have
above?  If anyone has any insight as to how fast a clock could be off of the
nominal 10 gigabit rate and still be considered compliant I would appreciate
it posted.

Thanks,

Joshua