RE: [802.3ae] A Questuin about D3.4/ 47, 48
Rich,
I do not think it has something to do with the 100ppm drift. Drift is
frequency deviation between two different clock domains, while jitter is the
deviation of a certain signal edge location from its nominal location,
regardless its frequency or other clock domain frequency.
I think that the interpretation of jitter is that Jitter=The deviation of a
certain bit edge from its nominal location. So, saying Jitter of 8.5 UI in
frequency 0 is allowed, as in figure 47-5, is saying that a certain point
may be misslocated by 8.5 UI. This can happen even with DRIFT=0.
For instance, suppose there is no skew at all, but lane 0 is jittering to
the right by 4 bits, and lane 1 to the left by 4.5 bits, and this happens in
jitter frequency=0, that is, in a very slow way. This implies that this
situation is almost constant. So there is is a skew of 8.5 bits between lane
0 and lane 1 although if there was not any jitter, the skew would be 0.
Otherwise, can somebody explain the meaning of the Sinusoidal jitter mask in
figure 47-5? What is happening there in the interval [0,22Khz]?
Boaz
> -----Original Message-----
> From: Rich Taborek [mailto:rtaborek@earthlink.net]
> Sent: Thursday, November 29, 2001 3:46 AM
> To: Boaz Shahar
> Cc: HSSG (E-mail)
> Subject: Re: [802.3ae] A Questuin about D3.4/ 47, 48
>
>
> What??? 8B/10B has a max run length of 5. This translates to a lowest
> frequency component of 312.5 MHz. This is slightly higher
> than 22 KHz.
>
> The "slanted" portion of Figure 47-5 is the low frequency mask and
> corresponds to the +/-100 ppm XAUI clock tolerance. At the really low
> frequencies, I believe that the 8.5 UI corresponds to the
> number of bits
> that would have to be buffered in the case that clock tolerance
> compensation is performed for a packet length equivalent to
> 22 kHz. The
> 8.5 UI and the slanted line itself has no relevance if clock tolerance
> compensation is not performed. The 8.5 UI is only relevant on
> a per lane
> basis and has no significance lane to lane. Therefore, the 41
> bit deskew
> in Table 48-5 holds.
>
> Best Regards,
> Rich
>
> --
>
> Boaz Shahar wrote:
> >
> > In clause 47, 47.3.4.6 and figure 47-5, the sinusoidal
> jitter is 8.5 UI in
> > very low frequency (Interval [0,22Khz]). This means that
> there is additional
> > skew of 8.5 UI between lanes in the XAUI. That is included
> in Table 48-5
> > (Skew Budget)? In other words, while doing de-skewing, one
> should consider
> > 41+8.5 as the max deskew situation or just 41?
> > Thx.,
> > Boaz
>
> ---------------------------------------------------------
> Richard Taborek Sr. Intel Corporation
> XAUI Sherpa Intel Communications Group
> 3101 Jay Street, Suite 110 Optical Group Marketing
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>
>