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[10GBASE-CX4] Re: 10GBASE-CX4- Compliance Channel Insertion loss:




Please note that the term "e" in the compliance insertion loss channel below
is ( -.5 dB)
 not (.5 dB) as originally given.

Insertion_Loss(f) < ((a*sqr(f))+(b*f)+(c*1/sqr(f)))+e (dB)

Where:

a = -2.25E-04
b = -6.08E-09
c = -2.08E+04
e = -.5 dB (Insertion Loss deviation)

Regards,

Chris


----- Original Message -----
From: "Chris DiMinico" <cd@mohawk-cdt.com>
To: <stds-802-3-10GBCX4@ieee.org>
Sent: Monday, December 23, 2002 11:36 AM
Subject: 10GBASE-CX4- Compliance Channel Insertion loss:


> Happy Holiday:
>
> 10GBASE-CX4- Compliance Channel Insertion loss:
>
> The insertion loss of each pair of the CX4 cable assembly shall be less
> than:
> Insertion_Loss(f) </= ((a*sqr(f))+(b*f)+(c*1/sqr(f)))+e (dB) at all
> frequencies from TBD(100 MHz)
> to (TBD)2 GHz. This includes the attenuation of the differential cabling
> pairs, and the assembly
> connector.
>
> Where:
>
> a = -2.25E-04 sqrtf
> b = -6.08E-09 f
> c = -2.08E+04 1/sqrtf
> e = .5 dB (Insertion Loss deviation)
>
> Regards,
>
> Chris DiMinico
>