Re: Undefined behaviour (Was: Definition of intervals as subsets...)
This was intended for the entire group. - Dan
To: Nate Hayes <nh@xxxxxxxxxxxxxxxxx>,
"R. Baker Kearfott" <rbk@xxxxxxxxxxxxx>
Cc: Dan Zuras Intervals <intervals08@xxxxxxxxxxxxxx>
From: Dan Zuras Intervals <intervals08@xxxxxxxxxxxxxx>
Subject: Re: Undefined behaviour (Was: Definition of intervals as subsets...)
Date: Mon, 16 Mar 2009 08:13:51 -0700
> Date: Mon, 16 Mar 2009 08:40:10 -0500
> From: "R. Baker Kearfott" <rbk@xxxxxxxxxxxxx>
> To: stds-1788 <stds-1788@xxxxxxxxxxxxxxxxx>
> Subject: Re: Undefined behaviour (Was: Definition of intervals as subsets...)
>
> Dear Michel, et. al.,
>
> > . . .
> >
>
> For example, the Kaucher interval addition
>
> [a,b]+[c,d]=[a+c,b+d]
>
> is the same as the classical formula except it
> relaxes the constraint a <= b and c <=d, i.e.,
>
> [5,2]+[3,9]=[8,11]
>
> is the correct modal result.
>
> . . .
>
> Sincerley,
>
> Nate Hayes
> Sunfish Studio, LLC
Nate,
Am I missing something here?
[5,2]+[3,9]=[8,11]
Can it really be that the sum of {x | 5 <= x or x <= 2}
and {y | 3 <= y <= 9} is {x+y | 8 <= x+y <= 11}?
Stated another way, can it really be that the sum of a
bifurcated interval of infinite width & an ordinary
interval of width 6 is an ordinary interval of width 3?
This appears non-intuitive at best or wrong at worst.
Can you explain this result?
Thanks,
Dan