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Re: 1/[0,2]=NaI

> To the best I understand, this is what John advocates in his
> proposal... that zero is dropped from the domain:
> 
>    1/[0,2] = 1/([0,2] \intersect (0,Inf)) = 1/(0,Inf) = [1/2,Inf).
> 


Oops. Of course I meant

    1/[0,2] = 1/([0,2] \intersect (0,Inf)) = 1/(0,2] = [1/2,Inf).

Nate