>No, you're also using the associativity here, because a+b+c is
>interpreted unambiguously as (a+b)+c. And from (a+b)+c to (a+c)+b,
>you're not using the commutativity only, but a succession of
>commutativity and associativity transformations.
No, that is NOT true, and never has been! Please stop propagating that
myth. The word that is false (and I mean false) is "unambiguously", and
without that it is still misleading. All that is unambiguous is the
PARSING - the evaluation has NEVER been clearly specified.
The evaluation is just a consequence of the parsing. If you follow the
grammar (which specifies expressions), a+b+c is equivalent to (a+b)+c,
and the C standard has no rules concerning explicit parentheses.
The interpretation of the C standard was drifting towards the parsing
order being the evaluation order, for different reasons, but WG14 has
NEVER clarified this point.
Remember that I was answering something related to F.8.2, so that we
are under the context of Annex F (IEEE 754 standard).