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Re: Revised version of Level 1 text (draft)



Arnold Neumaier wrote:
John Pryce wrote:
Arnold, P1788

Here are two examples for Arnold's specification of intersection of decorated intervals, using the (ill<emp<con<def<saf) scheme.

Example 1
---------
Suppose f(x) = |x| is represented in two (admittedly silly) ways as
  g(x) = |2x-x|
  h(x) = x sign(x)
(where sign(x) is -1 if x<0, 0 if x=0, 1 if x>0).
Let xx = [-1,1]. Then I get
gg = g(xx) = abs(2*xx-xx) = abs([-2,2]-[-1,1]) = abs([-3,3]) = [0,3] decorated dg = saf, hh = h(xx) = [-1,1]*sign([-1,1] = [-1,1]*[-1,1] = [-1,1] decorated dh = def. Each is a valid enclosure of range(f,xx) so let's improve it by taking the intersection. Arnold's recipe uses the dg>dh case and returns
  (ff,df) = (hh,dh) = ([-1,1],def),
not very good. Whereas my analysis suggests we should return
  (ff,df) = (gg intersection hh, max(dg,dh)) = ([0,1], saf)
which happens to be sharp in this case.

Your recipe
    (ff,df) = (gg intersection hh, max(dg,dh)) = ([0,1], saf)
is ok here but gives the wrong result if h(x) happens not to be defined everywhere, such as when using
     g(x)=|x|, h(x)=(sqrt(x))^2
My formula (corrected formulation below) was constructed in such a way that this case is still correct, which is important for my original example.

As Ned Nedialkov pointed out to me, the example
   g(x)=|x|, h(x)=(sqrt(x))^2
is not appropriate. It doesn't satisfy my stricter criterion below
but only the old version that was too permissive.

Sorry for having created confusion.



Indeed, here is no theoretical justification for an intersection. So my criterion for applicability should be formulated as follows: g and h must be valid expressions for the function of interest, except at isolated values of some argument.