Re: A motion for property tracking via decorations

["Nate Hayes" <nh@xxxxxxxxxxxxxxxxx>]

Hi Vladik,

I'm assuming the same formal definition for C(f,X) as was given by John in 
Section 4 of his (never voted on) motion 22, which I attach for convenience.

Nate

----- Original Message ----- 
From: "Kreinovich, Vladik" <vladik@xxxxxxxx>
To: "'Dan Zuras Intervals'" <intervals08@xxxxxxxxxxxxxx>; "Nate Hayes" 
<nh@xxxxxxxxxxxxxxxxx>
Cc: <stds-1788@xxxxxxxxxxxxxxxxx>
Sent: Friday, May 20, 2011 2:41 PM
Subject: RE: A motion for property tracking via decorations


> I assumed continuous means continuous at every point where it is defined? 
> This can be clarified. What is C1 continuous? Differentiable? This seems a 
> very non-standard terminology, but in any case, this needs to be clarified.
>
> -----Original Message-----
> From: stds-1788@xxxxxxxx [mailto:stds-1788@xxxxxxxx] On Behalf Of Dan 
> Zuras Intervals
> Sent: Friday, May 20, 2011 1:34 PM
> To: Nate Hayes
> Cc: stds-1788@xxxxxxxxxxxxxxxxx; Dan Zuras Intervals
> Subject: Re: A motion for property tracking via decorations
>
> > From: "Nate Hayes" <nh@xxxxxxxxxxxxxxxxx>
> > To: "P-1788" <stds-1788@xxxxxxxxxxxxxxxxx>
> > Subject: A motion for property tracking via decorations
> > Date: Fri, 20 May 2011 12:48:11 -0500
> >
> >
> > Dear P1788,
> >
> > I submit the attached PDF entitled "Property Tracking with Decorations" 
> > as a
> > new motion.
> >
> > Sincerely,
> >
> > Nate Hayes
>
> Nate,
>
> Some observations about your new motion:
>
> On page 2, 2.2 Decorations, the list of examples includes
> the entry:
>
> S(sqrt,[0,4]) = D3.
>
> This suggests to me that earlier on page 1, Definition 1,
> the continuous you are describing is C0 continuous.  Were
> it C1 continuous or anything higher the answer to sqrt([0,4])
> would be D2 (defined but NOT continuous).  In that case we
> would have:
>
> S(sqrt,[0,4]) = D2, &
> S(sqrt,[1,4]) = D3.

Attachment: JDPdiscontinuousbitV3.pdf
Description: Adobe PDF document