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Nate Am 01.07.2011 17:09, schrieb Nate Hayes:
I think 1 is a discontinuity point of the floor function, hence both cases are defined onlyOne other comment: What about floor([1,3/2])? I would think it should be defined and continuous, i.e., "safe", since when restricted to the domain [1,3/2] the floor function at 1 is defined and continuous when approached from the right and cannot be approached from the left. But it seems this would imply floor([1,1]) should also be "safe"; but motion 27 gives "defined" for this example? Nate
Juergen