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Re: Definition of intervals as subsets of R - the bad news



Siegfried, Arnold and all

On 19 Feb 2009, at 13:50, Arnold Neumaier wrote:
I don't see why this makes expensive alterations necessary.
Convert any real +-inf to NaN before doing the standard operation,
and you get the correct result.

Setting x(isinf(x))=NaN before executing an operation with a
real argument x is cheap, vectorizes, and should do the trick.

That's what I was about to propose. On the assumption (my preference) that any real x is regarded as [x,x] if finite, and emptyset if infinite, this seems to work for aa+b, aa-b, aa*b, aa/b, as well with the arguments swapped. What am I missing?

John