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Re: A question Re: Level 1 <---> level 2 mappings; arithmetic versus applications



> From: "Nate Hayes" <nh@xxxxxxxxxxxxxxxxx>
> To: "Dan Zuras Intervals" <intervals08@xxxxxxxxxxxxxx>,
> 	"Ralph Baker Kearfott" <rbk@xxxxxxxxxxxx>
> Cc: "P-1788" <stds-1788@xxxxxxxxxxxxxxxxx>,
> 	"Dan Zuras Intervals" <intervals08@xxxxxxxxxxxxxx>
> Subject: Re: A question Re: Level 1 <---> level 2 mappings; arithmetic versus applications
> Date: Wed, 30 Jun 2010 15:05:39 -0500
> 
> Dan Zuras wrote:
> 
> . . .
> 
> John has previously made the observation that there is an exact mapping from
> Level 2 mid-rad interval to Level 1 interval. Of course, once at Level 1
> there is then also an exact mapping from mid-rad to inf-sup (or vice-versa).
> So the only conversion that requires care is mapping back from Level 1 to
> Level 2. However, it seems there is some Level 1 mid-rad interval
> corresponding to some Level 2 mid-rad interval that is provably the tightest
> possible Level 2 enclosure, so long as that Level 2 enclosure is represented
> by a midpoint and a radius.
> 
> . . .
> 
> Nate
> 

	Nate,

	I am going to pass on most of the content of your note
	to focus on this one statement because the fact that
	you state things in this way means I have not been
	clear.

	Level 1 is the set of all possible contiguous subsets
	of the extended Reals.

	Therefore there ARE NO mid-rad or inf-sups at level 1.
	Representations have no meaning there.

	Level 2 is some finite subset of the intervals that exist
	at level 1.

	What I am proposing is that the DEFINING characteristic
	of that subset be that the bounds be exactly (some say,
	losslessly) extractable as elements of some floating-point
	type F.

	Therefore, there are no mid-rad or inf-sups at level 2
	either.  Representations have no more meaning here then
	they do at level 1.

	All the formats live at lower levels.

	And I am proposing an approach that never speaks of them
	directly while still knowing that they exist & taking
	care that some agreeable behavior is possible for them.

	That's all.


				Dan