Re: KISS-decorations
- To: "Kreinovich, Vladik" <vladik@xxxxxxxx>
- Subject: Re: KISS-decorations
- From: "Corliss, George" <george.corliss@xxxxxxxxxxxxx>
- Date: Sat, 2 Jul 2011 14:21:28 +0000
- Accept-language: en-US
- Cc: "Corliss, George" <george.corliss@xxxxxxxxxxxxx>, Nate Hayes <nh@xxxxxxxxxxxxxxxxx>, Jürgen Wolff von Gudenberg <wolff@xxxxxxxxxxxxxxxxxxxxxxxxxxx>, John Pryce <j.d.pryce@xxxxxxxxxxxx>, Dominique Lohez <dominique.lohez@xxxxxxx>, "stds-1788@xxxxxxxx" <stds-1788@xxxxxxxx>
- Delivered-to: mhonarc@xxxxxxxxxxxxxxxx
- In-reply-to: <4C5F914ECF9F5F4CA2DB475171D055C3B899D33104@xxxxxxxxxxxxxxxxxxxx>
- List-help: <http://listserv.ieee.org/cgi-bin/wa?LIST=STDS-1788>, <mailto:LISTSERV@LISTSERV.IEEE.ORG?body=INFO%20STDS-1788>
- List-owner: <mailto:STDS-1788-request@LISTSERV.IEEE.ORG>
- List-subscribe: <mailto:STDS-1788-subscribe-request@LISTSERV.IEEE.ORG>
- List-unsubscribe: <mailto:STDS-1788-unsubscribe-request@LISTSERV.IEEE.ORG>
- References: <4E0A35F4.3020001@xxxxxxxxxxxxxxxxxxxxxxxxxxx> <77CF7C97-5819-448D-91FE-92F2A7E37009@xxxxxxxx> <4E0B0913.7060903@xxxxxxxxxxxxxxxxxxxxxxxxxxx> <4E0C5308.7040306@xxxxxxx> <8A47C77A-6353-4CA5-9919-948FAC87FB4A@xxxxxxxxxxxx> <4E0DAF2E.4020204@xxxxxxxxxxxxxxxxxxxxxxxxxxx> <ACE62C6992C8465BB805B34FC4FA80F9@KLENDATHU> <4E0E273C.7090406@xxxxxxxxxxxxxxxxxxxxxxxxxxx>,<3B1DB6B9F8604F93B9CB5F0C3E3ECB13@KLENDATHU> <4C5F914ECF9F5F4CA2DB475171D055C3B899D33104@xxxxxxxxxxxxxxxxxxxx>
- Sender: stds-1788@xxxxxxxx
- Thread-index: AQHMNdB2b+ufoDG2FUezmvLcb8+ujAAibqZ3lNhbZQA=
- Thread-topic: KISS-decorations
Vladik,
Did you look at the interval argument before you made your comment? For floor([1, 3/2]) = 1, which IS continuous in the calculus epsilon-delta sense.
Or am I missing something?
George
On Jul 2, 2011, at 9:07 AM, Kreinovich, Vladik wrote:
> Of course, the notion of contnuity depends on topology, but when people talk about continuity without explaining what this means, they mean continuity in the normal calculus epsilon-delta sense in which the floor function is clearly NOT continuous.
>
> ________________________________________
> From: stds-1788@xxxxxxxx [stds-1788@xxxxxxxx] On Behalf Of Nate Hayes [nh@xxxxxxxxxxxxxxxxx]
> Sent: Friday, July 01, 2011 3:37 PM
> To: Jürgen Wolff von Gudenberg
> Cc: John Pryce; Dominique Lohez; stds-1788@xxxxxxxx
> Subject: Re: KISS-decorations
>
> I'm thinking along the lines of Definition 2.2.3 on pp. 55-56 in:
> http://ramanujan.math.trinity.edu/wtrench/texts/TRENCH_REAL_ANALYSIS.PDF
> By that definition, wouldn't
> floor([1,3/2])
> be continuous?
>
> Nate
>
>
> ----- Original Message -----
> From: "Jürgen Wolff von Gudenberg" <wolff@xxxxxxxxxxxxxxxxxxxxxxxxxxx>
> To: "Nate Hayes" <nh@xxxxxxxxxxxxxxxxx>
> Cc: "John Pryce" <j.d.pryce@xxxxxxxxxxxx>; "Dominique Lohez"
> <dominique.lohez@xxxxxxx>; "stds-1788@xxxxxxxx" <stds-1788@xxxxxxxx>
> Sent: Friday, July 01, 2011 2:59 PM
> Subject: Re: KISS-decorations
>
>
>> Nate
>>
>> Am 01.07.2011 17:09, schrieb Nate Hayes:
>>> One other comment:
>>>
>>> What about
>>> floor([1,3/2])?
>>> I would think it should be defined and continuous, i.e., "safe", since
>>> when
>>> restricted to the domain [1,3/2] the floor function at 1 is defined and
>>> continuous when approached from the right and cannot be approached from
>>> the
>>> left.
>>>
>>> But it seems this would imply
>>> floor([1,1])
>>> should also be "safe"; but motion 27 gives "defined" for this example?
>>>
>>> Nate
>>>
>> I think 1 is a discontinuity point of the floor function, hence both cases
>> are defined only
>> Juergen
>>
Dr. George F. Corliss
Electrical and Computer Engineering
Marquette University
P.O. Box 1881
1515 W. Wisconsin Ave
Milwaukee WI 53201-1881 USA
414-288-6599; GasDay: 288-4400; Fax 288-5579
George.Corliss@xxxxxxxxxxxxx
www.eng.mu.edu/corlissg